![]() Such that this, let's call this A, that matrix A. ![]() So that means A times x has toīe equal to this or has to be equal to that. To find all of the x's that satisfy, the first one right We essentially have to justįind all of the x's that satisfy these two equations I just made it a little bit moreĮxplicit in terms of our actual transformation, Or A times our vector x has toīe equal to this vector 1,2. ![]() T is going to be all the solutions to this plus all of All of the solutions to this,Īll of the x's that satisfy this, is the null space Here is the matrix 1, 3, 2, 6 times x1, x2 is equal
0 Comments
Leave a Reply. |